2x^2+2y^2-12x+4y=15

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Solution for 2x^2+2y^2-12x+4y=15 equation: 


Simplifying
2x2 + 2y2 + -12x + 4y = 15

Reorder the terms:
-12x + 2x2 + 4y + 2y2 = 15

Solving
-12x + 2x2 + 4y + 2y2 = 15

Solving for variable 'x'.

Reorder the terms:
-15 + -12x + 2x2 + 4y + 2y2 = 15 + -15

Combine like terms: 15 + -15 = 0
-15 + -12x + 2x2 + 4y + 2y2 = 0

The solution to this equation could not be determined.

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